Questions

*ABC* is right angled triangular plane of uniform thickness. The sides are such that *AB* >* BC* as shown in figure. *I*_{1,} *I*_{2}, *I*_{3} are moments of inertia about *AB, BC* and *AC*, respectively. Then, which of the following relations is correct? UIPMER 2017]

60 mins Expert Faculty Ask Questions

a

I1=I2=I3

b

I2>I1>I3

c

I3

d

I3>I1>I2

detailed solution

Correct option is B

The moment of inertia of a body about an axis depends not only on the mass of the body but also on the distribution of mass about the axis. For a given body, mass is same, so it will depend only on the distribution of mass about the axis. The mass is farthest from axis BC, so I2 is maximum, mass is nearest to axis AC, so I3 is minimum.Hence, the correct sequence will be I2>I1>I3

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Two discs have mass ratio 1 : 2 and diameter ratio 2 : 1, then find the ratio of their moments of inertia.

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