ABC is right angled triangular plane of uniform thickness. The sides are such that AB BC as shown in figure. $$I1$$, $$I2$$, $$I3$$ are moments of inertia about AB, BC and AC, respectively. Then, which of the following relations is correct? UIPMER $$2017$$]

Question

ABC is right angled triangular plane of uniform thickness. The sides are such that AB > BC as shown in figure. $$I1$$, $$I2$$, $$I3$$ are moments of inertia about AB, BC and AC, respectively. Then, which of the following relations is correct? UIPMER $$2017$$]

Infinity Learn · Accepted Answer

The moment of inertia of a body about an axis depends not only on the mass of the body but also on the distribution of mass about the axis. For a given body, mass is same, so it will depend only on the distribution of mass about the axis. The mass is farthest from axis BC, so $$I2$$ is maximum, mass is nearest to axis AC, so $$I3$$ is minimum.Hence, the correct sequence will be  $$I2$$>$$I1$$>$$I3$$

ABC is right angled triangular plane of uniform thickness. The sides are such that AB > BC as shown in figure. I_1, I₂, I₃ are moments of inertia about AB, BC and AC, respectively. Then, which of the following relations is correct? UIPMER 2017]

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ABC is right angled triangular plane of uniform thickness. The sides are such that AB > BC as shown in figure. I1, I2, I3 are moments of inertia about AB, BC and AC, respectively. Then, which of the following relations is correct? UIPMER 2017]

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ABC is right angled triangular plane of uniform thickness. The sides are such that AB > BC as shown in figure. I_1, I₂, I₃ are moments of inertia about AB, BC and AC, respectively. Then, which of the following relations is correct? UIPMER 2017]