Questions

ABC is right angled triangular plane of uniform thickness. The sides are such that AB > BC as shown in figure. I1, I2, I3 are moments of inertia about AB, BC and AC, respectively. Then, which of the following relations is correct? UIPMER 2017]

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a
I1=I2=I3
b
I2>I1>I3
c
I3
d
I3>I1>I2

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detailed solution

Correct option is B

The moment of inertia of a body about an axis depends not only on the mass of the body but also on the distribution of mass about the axis. For a given body, mass is same, so it will depend only on the distribution of mass about the axis. The mass is farthest from axis BC, so I2 is maximum, mass is nearest to axis AC, so I3 is minimum.Hence, the correct sequence will be  I2>I1>I3

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