ABCD is a composite slab made of two slabs of transparent materials having refractive indices μ1=43 and μ2=32. P is a small object. For near normal vision from top of the composite slab, the apparent position of the object P i.e. at the interface of the slabs. Then the ratio t1t2 is

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answer is A.

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Detailed Solution

Apparent depth =t1μ1+t2μ2∴ t1μ1+t2μ2=t1⇒t1t2=1/μ21−2/μ1=2/31−34=83

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