In an ac circuit, V and I are given by V = 100 sin (100 t) volts, I=100sin 100t+π3 mA. The power dissipated in circuit is
104 watt
10 watt
2.5 watt
5 watt
P=Vr.m.s.×ir.m.s.×cosφ=1002×100×10−32×cosπ3
=104×10−32×12=104=2.5 watt