In an AC circuit, V and I are given by V=100 sin(100t) volts, I=100sin100t+π3 mA. The power dissipated in the circuit is
104 watt
10 watt
2.5 watt
5 watt
P=Vr.m.s. ×ir.m.s. ×cosϕ=1002×100×10−32×cosπ3
=104×10−32×12=104=2.5 watt