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Q.

An AC rms voltage of 2 V having a frequency of 50 kHz is applied to a condenser of capacity of 10 μF. The maximum value of the magnetic field between the plates of the condenser, if the radius of plate is 10 cm is

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a

0.4 π μT

b

4 π μT

c

42 π μT

d

40 π μT

answer is C.

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Detailed Solution

i0=V0XC =2VrmsXC =2Vrms1ωc =2Vrms ω c =2 x 2 x 2π x 50 x 103 x 10 x 10-6 =2π2 Amp∮ B¯.dl¯=μ0i0B.2πR=μ0i0 ; B.2π 10-1=4π x 10-7×2π2B=42π μT
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