An AC source has an internal resistance of 104Ω. The turn ratio of a transformer so as to match the source to a load of resistance10Ω is
4.62× 10−2
2.03× 10−2
3.16× 10−2
5.62× 10−2
Power = VS IS = VP IP VS . VSZS=VP . VPZP
∴ NsNp= VSVP=ZSZP =1010,000 = 3.16 × 10−2.