An AC source has an internal resistance of 104Ω. The turn ratio of a transformer so as to match the source to a load of resistance10Ω is

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4.62× 10−2

2.03× 10−2

3.16× 10−2

5.62× 10−2

answer is C.

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Detailed Solution

Power = VS IS = VP IP VS . VSZS=VP . VPZP∴ NsNp= VSVP=ZSZP =1010,000 = 3.16 × 10−2.

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