Questions
The acceleration of block B in the figure will be
a
m2g4m1+m2
b
2m2g4m1+m2
c
2m1gm1+4m2
d
2m1gm1+m2
detailed solution
Correct option is A
When block m2 moves downward with acceleration a, the acceleration of mass rn I will be 2a because it covers double distance in the same time in comparison to m2.Let T be the tension in the string. By drawing the free body diagram of A and B, T=m12a .......(i)m2g−2T=m2a ......(ii)By solving (i) and (ii),a=m2g4m1+m2Talk to our academic expert!
Similar Questions
For the system shown in figure, the pulleys are light and frictionless. The tension in the string will be
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