Questions
The acceleration of the blocks (A) and (B) respectively in situation shown in the flgure is: (pulleys and strings are massless)
detailed solution
Correct option is
The F.B.D. of block A and B arefrom constraint, the acceleration of A and B are ‘2a’ and ‘a’ respectively. Applying Newton's second law to blocks A and B, we get4g-T = 4(2a)---------(i)2T-5g = 5(a) ---------(ii)Solving we get acceleration of A and B as 2g7Talk to our academic expert!
Similar Questions
Two masses of I kg and 5 kg are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in figure. The masses start moving during this interval; the reading of spring balance will be:
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