The acceleration due to gravity on the earth’s surface at the poles is g and angular velocity of the earth about the axis passing through the pole is ω. An object is weighed at the equator and at a height h above the poles by using a spring balance. If the weights are found to be same, then h is : (h <

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R2ω28g

R2ω2g

R2ω24g

R2ω22g

answer is D.

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Detailed Solution

Weight of the object near the equator = mg−Rω2And at height h near the poles = mgR2R+h2Given mg−Rω2=mgR2R+h2=mg1−2hR,⇒mg−Rω2=mg1−2hR ∵h<

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