First slide

Variation of g

Question

The acceleration due to gravity at a height 1 km above the earth is the same as at a depth of below the surface of earth. Then:

Easy

A

d = 2km
B

d = 1/2 km
C

d = 1 km
D

d = 3/2 km

Solution

$\large {g}' = g\left( {1 - \frac{{2h}}{R}} \right) \to (1)\,\,with\,height$
$\large {g}' = g\left( {1 - \frac{d}{R}} \right) \to (2)\,\,with\,depth$
$\large \frac{{2h}}{R} = \frac{d}{R} \Rightarrow d = 2h \Rightarrow d = 2km$

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