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The acceleration due to gravity on moon is ${\frac{1}{6}}^{th}$ of that on the earth. If the length of the seconds pendulum is 96 cm on the earth, what is its length on the moon?

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Correct option is A

Given gm=16ge=ge6And le=96 cms For seconds pendulum time period is 2 seconds.T=2πlg for simple pendulum Time remains constant in both the planets.lg=constant.lmle=gmgelm=le×gmge=96×ge6ge=966=16 cms. length of seconds pendulum on moon = 16cm

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The acceleration due to gravity on moon is 16th of that on the earth. If the length of the seconds pendulum is 96 cm on the earth, what is its length on the moon?

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The acceleration due to gravity on moon is ${\frac{1}{6}}^{th}$ of that on the earth. If the length of the seconds pendulum is 96 cm on the earth, what is its length on the moon?