First slide

Variation of g

Question

The acceleration due to gravity on the planet A is 9 times the acceleration due to the gravity on planet B. A man jumps to a height of 2 m on the surface of A. What is the height of jump by the same person on the planet B

Easy

A

18m
B

6m
C

$\frac{2}{3} m$
D

$\frac{2}{9} m$

Solution

We know that acceleration due to gravity decreases with height, i.e., $g \propto 1 / h$
$∴ \frac{g_{A}}{g_{B}} = \frac{h_{B}}{h_{A}} or h_{B} = (\frac{g_{A}}{g_{B}}) \times h_{A}$
or $h_{B} = (\frac{9 g_{B}}{g_{B}}) \times 2 = 18 m$

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