First slide

Periodic Motion

Question

The acceleration due to gravity on a planet is 3/2 times that on the earth. If length of a seconds pendulum on earth is 1m, length of seconds pendulum on surface of planet is

Easy

A

0.7m
B

1m
C

1.7m
D

1.5m

Solution

$\sqrt{\frac{l}{g}} = constant$

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