The acceleration due to gravity at the poles and the equator is $g_{p} and g_{e}$ respectively. If the earth is a sphere of radius $R_{E}$ and rotating about its axis with angular speed
$ω$ , then $g_{p} - g_{e}$ is given by

Question

Infinity Learn · Accepted Answer

Acceleration due to gravity at a place of latitude λ due to the rotation of earth isg' $$=$$ $$g-RE$$ω$$2cos2$$λAt equator, λ $$=$$ $$00$$, $$cos00$$ $$=$$ $$1$$∴ g' $$=ge$$ $$=g-Rg$$ω$$2At$$ poles, λ $$=$$ $$90$$°, $$cos$$ $$90$$° $$=$$ $$0$$∴ g' $$=$$ gp $$=g$$∴ $$gp-ge$$ $$=$$ $$g-(g-RE$$ω$$2)$$ $$=$$ REω$$2$$

The acceleration due to gravity at the poles and the equator is $g_{p} and g_{e}$ respectively. If the earth is a sphere of radius $R_{E}$ and rotating about its axis with angular speed
$ω$ , then $g_{p} - g_{e}$ is given by

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The acceleration due to gravity at the poles and the equator is gp and ge respectively. If the earth is a sphere of radius RE and rotating about its axis with angular speedω, then gp-ge is given by

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The acceleration due to gravity at the poles and the equator is $g_{p} and g_{e}$ respectively. If the earth is a sphere of radius $R_{E}$ and rotating about its axis with angular speed
$ω$ , then $g_{p} - g_{e}$ is given by