The acceleration due to gravity on the surface of the moon is $$1.7m/s2$$. What is the time period of a simple pendulum on the surface of moon if it’s time period on the surface earth is $$3.5$$ seconds?(g$$ on the surface of earth is $$9.8m/s2).

Question

The acceleration due to gravity on the surface of the moon is $$1.7m/s2$$. What is the time period of a simple pendulum on the surface of moon if it’s time period on the surface earth is $$3.5$$ seconds?(g$$ on the surface of earth is $$9.8m/s2).

Infinity Learn · Accepted Answer

acceleration dure to gravity,  $$gmoon=gm=1.7ms-2$$   $$gearth=ge=9.8ms-2$$ time period on earth is $$Tearth=Te=3.5s-1$$ As $$Te=2$$$$π$$$$lge---(1)$$ time period on moon $$=$$ $$Tmoon=Tm=2$$$$π$$$$lgm---(2)$$ divide equation (2) by (1) $$TmTe=gegm$$ $$Tm=Tegegm$$ $$Tm=3.59.81.7=8.4$$ seconds

The acceleration due to gravity on the surface of the moon is $1.7 m / s^{2}$ . What is the time period of a simple pendulum on the surface of moon if it’s time period on the surface earth is 3.5 seconds?(g on the surface of earth is $9.8 m / s^{2}$ ).

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The acceleration due to gravity on the surface of the moon is 1.7m/s2. What is the time period of a simple pendulum on the surface of moon if it’s time period on the surface earth is 3.5 seconds?(g on the surface of earth is 9.8m/s2).

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The acceleration due to gravity on the surface of the moon is $1.7 m / s^{2}$ . What is the time period of a simple pendulum on the surface of moon if it’s time period on the surface earth is 3.5 seconds?(g on the surface of earth is $9.8 m / s^{2}$ ).