The acceleration due to gravity on the surface of the moon is 1.7m/s2. What is the time period of a simple pendulum on the surface of moon if it’s time period on the surface earth is 3.5 seconds?(g on the surface of earth is 9.8m/s2).

Given gm=1.7ms-2 ge=9.8ms-2Time period on Earth=Te=3.5seconds                                    As Te=2πlge Time period on moon=Tm=2πlgm ratio of above two equations is,                                            TmTe=gegm                                              Tm=Tegegm                                               Tm=3.59.81.7=8.4 seconds