First slide
Coulumbs law
Question

The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1.6 Å apart is,

me9×1031kg,e=1.6×1019C (Take 14πε0=9×109Nm2C2

Very Easy
Solution

F=e24πε0r2ae=Fmeae=e24πε0mer2ae=9×109×(1.6)2×10389×1031×(1.6)2×1020ae=1022m/s2

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