The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1.6 Å apart is,
me≃9×10−31kg,e=1.6×10−19C (Take 14πε0=9×109Nm2C−2
1025 m/s2
1024 m/s2
1023 m/s2
1022 m/s2
F=e24πε0r2ae=Fmeae=e24πε0mer2ae=9×109×(1.6)2×10−389×10−31×(1.6)2×10−20ae=1022m/s2