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Questions  

The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is 1.76×1011C/kg, is 

a
8.8×1014 m/sec2
b
6.2×1013 m/sec2
c
5.4×1012 m/sec2
d
Zero

detailed solution

Correct option is A

a=eEm⇒ a=1.76×1011×50×102=8.8×1014 m​/​s2

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