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Rectilinear Motion

Question

Acceleration of particle moving rectilinearly is a = 4 - 2x (where x is position in metre and a in m s-2). It is at instantaneous rest at x = 0. At what position x (in meter) will the particle again come to instantaneous rest?

Moderate
Solution

vdvdx=42x 0vvdv=0x(42x)dxv22=4xx2

when v = 0, 4x - x2 = 0

   x = 0, 4
 Thus, at x = 4, the particle will again come to rest.



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