The acceleration of particle varies with time as shown.Calculate the displacement of the particlein m in the interval from t=2 s to t=4 s. Assume that v=0 at t=0.
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answer is 6.67.
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Detailed Solution
a=2t-2 (from the graph)Now, ∫0vdv=∫0tadt=∫0t(2t-2)dt∴ v=t2-2tdsdt=t2-2t ⇒∫0s ds=∫24t2ddt-∫242tdt ⇒s=203 m