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The acceleration of a particle which moves along the positive x-axis varies with its position as shown in figure. If the velocity of the particle is 0.8 ms-1 at x = 0, then velocity of the particle at x = 1.4 m is (in ms-1

a
1.6
b
1.2
c
1.4
d
none of these

detailed solution

Correct option is B

a=vdvdx⇒∫uv vdv=∫01.4 adx⇒ v2−u22= Area of a−x graph ⇒v2−(0.8)2=2(0.4)⇒v=1.2ms−1

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