The acceleration time graph of a particle moving in a straight line is as shown in figure. The velocity of the particle at time t = 0 is 2 m/s. The velocity after 2 s will be

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6 m/s

4 m/s

2 m/s

8 m/s

answer is A.

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Detailed Solution

Area under a-t graph gives the change in velocity (dV = adt) ∴ vf−vi =12×2×4=4m/s ∴ vf=vi+4=2+4=6m/s

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