The acceleration - time graph of a particle moving in a straight line is shown in the fig. The velocity of the particle at time t = 0 is 2ms−1. The velocity after 2 seconds will be

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4 ms−1

6 ms−1

2 ms−1

8 ms−1

answer is B.

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Detailed Solution

Area under a-t graph gives change in velocity.Vf - Vi = [Area under the graph] = 1224=4Vf = 2+4 = 6m/s

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