Questions
The acceleration versus time graph of a particle moving in a straight line is shown in figure. The velocity-time graph of the particle would be
detailed solution
Correct option is B
a=−42t+4⇒a=−2t+4 v=∫adt+C=∫(−2t+4)dt+C=−t2+4t+CHence, graph will be parabolic.Talk to our academic expert!
Similar Questions
The acceleration of a particle starting from rest and travelling along a straight line is shown in figure. The maximum speed of the particle is
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