Q.

The acceleration versus time graph of a particle moving in a straight line is shown in figure. The velocity-time graph of the particle would be

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a

A straight line

b

A parabola

c

A circle

d

An ellipse

answer is B.

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Detailed Solution

a=−42t+4⇒a=−2t+4v=∫adt+C=∫(−2t+4)dt+C=−t2+4t+CHence, graph will be parabolic.
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The acceleration versus time graph of a particle moving in a straight line is shown in figure. The velocity-time graph of the particle would be