Questions
Acceleration-time graph of a particle moving in a straight line is as shown in below figure. Velocity of particle at time . Find the velocity at the end of fourth second.
detailed solution
Correct option is B
∫dv=∫adtChange in velocity = area under a-t graph.Hence, vf-vi=12(4)(4) =8m/svf=vi+8=(2+8)m/s =10 m/sTalk to our academic expert!
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A particle starts its motion from rest and moves with constant acceleration for time t1 and then it retards with constant rate for time t2 until it comes to rest. Then the ratio of maximum speed and average speed during the complete motion will be
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