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Q.

Acceleration-time graph of a particle moving in a straight line is as shown in figure. At tin t=0, velocity of the particle is zero, Find velocity of the particle at t=14 s?

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a

180 m/s

b

108 m/s

c

100 m/s

d

90 m/s

answer is D.

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Detailed Solution

Δv=vf-vi= net area of a-t graph∴  v14-v0=40+30+40-20=90  But   v0=0 ∴  v14=90 m/s
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