Acceleration-time graph of a particle moving in a straight line is as shown in figure. At tin t=0, velocity of the particle is zero, Find velocity of the particle at t=14 s?
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a
180 m/s
b
108 m/s
c
100 m/s
d
90 m/s
answer is D.
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Detailed Solution
Δv=vf-vi= net area of a-t graph∴ v14-v0=40+30+40-20=90 But v0=0 ∴ v14=90 m/s