The acceleration-velocity graph of a particle moving in a straight line is shown in figure. Then the slope of the velocity-displacement graph
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
increases linearly
b
decreases linearly
c
is constant
d
increases parabolically
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Acceleration-velocity equation from the graph is a = kv, where k is the slope of given line. This can also be written as vdvds=kv ⇒ dvds=ki.e. slope of velocity-displacement graph is same as slope of acceleration-velocity graph which is constant.