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Q.

The acceleration-velocity graph of a particle moving in a straight line is shown in figure. Then the slope of the velocity-displacement graph

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a

increases linearly

b

decreases linearly

c

is constant

d

increases parabolically

answer is C.

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Detailed Solution

Acceleration-velocity equation from the graph is a = kv, where k is the slope of given line. This can also be written as        vdvds=kv ⇒ dvds=ki.e. slope of velocity-displacement graph is same as slope of acceleration-velocity graph which is constant.
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The acceleration-velocity graph of a particle moving in a straight line is shown in figure. Then the slope of the velocity-displacement graph