Q.
According to Bohr's theory, the expressions for the kinetic and potential energy of an electron revolving in an orbit is given respectively by
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a
+e28πε0r and -e24πε0r
b
+8πε0e2r and -4πε0e2r
c
-e28πε0r and -e24πε0r
d
+e28πε0r and +e24πε0r
answer is A.
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Detailed Solution
P.E. =-ke2r=-e24πε0r; K.E.=-12(P.E.)=e28πε0r
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