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Q.

According to Bohr's theory, the expressions for the kinetic and potential energy of an electron revolving in an orbit is given respectively by

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a

+e28πε0r and -e24πε0r

b

+8πε0e2r and -4πε0e2r

c

-e28πε0r and  -e24πε0r

d

+e28πε0r and +e24πε0r

answer is A.

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Detailed Solution

P.E. =-ke2r=-e24πε0r; K.E.=-12(P.E.)=e28πε0r
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