First slide

Wave nature of matter

Question

According to de-Broglie, the de-Broglie wavelength for electron in an orbit of hydrogen atom is 10^-9 m. What is the principal quantum number for this electron?

Moderate

Solution

$2 π r n = λ \Rightarrow n = \frac{λ}{2 π r} = \frac{10^{- 9}}{2 \times 3.14 \times 5.13 \times 10^{- 11}} = 3$

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