First slide

Internal energy

Question

According to equipartition law of energy each particle in a system of particles have thermal energy E equal to

Moderate

A

$E = k_{B} T$
B

$E = \frac{1}{2} k_{B} T$
C

$E = 3 k_{B} T$
D

$E = \frac{3}{2} k_{B} T$

Solution

A particle has 3 degrees of freedom. Taking $\frac{1}{2} k_{B} T$ energy in each direction, we get total energy $E = \frac{3}{2} k_{B} T$

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