According to Joule's law of heating, the heat produced H=I2Rt where I is current, R is resistance and t is time. If the error in the measurement of I, R and t are 3%, 4% and 6% respectively then the error in the measurement of H is:

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±17%

±16%

±19%

±25%

answer is B.

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Detailed Solution

H=I2Rt∴ΔHH×100=2ΔII+ΔRR+Δtt×100=(2×3+4+6)%=16%

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