According to Newton's second law of motion, resultant force on a particle is in the direction of acceleration of the particle.Two forces F1 and F2 are acting on a particle as shown in the figure. The acceleration of the particle is along X-axis. The value of F1 (in newton) is

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answer is 0006.00.

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Detailed Solution

Since, acceleration of particle is along X-axis. So, net forces will be along X-axis. Hence, ∑FY=0∴F2sin⁡37∘−F1sin⁡30∘=0 or 35F2=F12∴ F1=65×5=6N

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