Q.

According to Newton's second law of motion, resultant force on a particle is in the direction of acceleration of the particle.Two forces F1 and F2 are acting on a particle as shown in the figure. The acceleration of the particle is along X-axis. The value of F1 (in newton) is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 0006.00.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Since, acceleration of particle is along X-axis. So, net forces will be along X-axis. Hence, ∑FY=0∴F2sin⁡37∘−F1sin⁡30∘=0 or 35F2=F12∴ F1=65×5=6N
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon
According to Newton's second law of motion, resultant force on a particle is in the direction of acceleration of the particle.Two forces F1 and F2 are acting on a particle as shown in the figure. The acceleration of the particle is along X-axis. The value of F1 (in newton) is