The accuracy of measurement also lies in the way the result is expressed. The number of digits to which a value is to be expressed is one digit more than number of sure numbers. Rules do exist to deal with number of digits after an operation is carried out on the given values. The error can be minimised by many trials and using the correct methods and instruments.If the length and breadth are measured as $$4.234$$ and $$1.05$$ m, the area of the rectangle is The order of magnitude of $$147$$ isThe number of significant figures can reduce in

Question

The accuracy of measurement also lies in the way the result is expressed. The number of digits to which a value is to be expressed is one digit more than number of sure numbers. Rules do exist to deal with number of digits after an operation is carried out on the given values. The error can be minimised by many trials and using the correct methods and instruments.If the length and breadth are measured as $$4.234$$ and $$1.05$$ m, the area of the rectangle is The order of magnitude of $$147$$ isThe number of significant figures can reduce in

Infinity Learn · Accepted Answer

$$A=lb=4.4457$$ $$m2=4.45$$ $$m2One$$ should retain only three significant figures.For x to be order of magnitude, $$0.5$$<$$14710x$$≤$$5$$ should be satisfied.To find say difference between $$20.17$$ and $$20.15$$, we get $$0.02$$ (i$$.e., one significant figure $$only).

Q.

Unlock the Full Solution and Master the Concept