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Q.

Activities of three radioactive substances A,B and C are represented by the curves  A,B and C in the figure . Then their half lives T12A:T12B:T12C:  are in the ratio :

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a

2 : 1  : 3

b

4 : 3  : 1

c

3 : 2  : 1

d

2 : 1  : 1

answer is A.

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Detailed Solution

Activity, R=R02-tth ⇒lnR=lnR0 -ln2thtComparing with straight line, y=c+mx , slope=m=-ln2thmA=6/10  from slopemB=6/5mC=2/5Since, slope ∝1half life⇒TA:TB:TC=106:56:52 = 20:10:30=2:1:3
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