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Activities of three radioactive substances A,B and C are represented by the curves A,B and C in the figure . Then their half lives $T_{\frac{1}{2}} (A) {:T}_{\frac{1}{2}} (B) {:T}_{\frac{1}{2}} (C) :$ are in the ratio :

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Correct option is A

Activity, R=R02-tth ⇒lnR=lnR0 -ln2thtComparing with straight line, y=c+mx , slope=m=-ln2thmA=6/10 from slopemB=6/5mC=2/5Since, slope ∝1half life⇒TA:TB:TC=106:56:52 = 20:10:30=2:1:3

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Activities of three radioactive substances A,B and C are represented by the curves A,B and C in the figure . Then their half lives T12A:T12B:T12C: are in the ratio :

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free study material

Activities of three radioactive substances A,B and C are represented by the curves A,B and C in the figure . Then their half lives $T_{\frac{1}{2}} (A) {:T}_{\frac{1}{2}} (B) {:T}_{\frac{1}{2}} (C) :$ are in the ratio :