First slide

Radioactivity - Nuclei

Question

Activity of a radioactive element decreased to one third of original activity $I_{0}$ in 9 years. After further 9years, its activity will be

Easy

A

$I_{0}$
B

$\frac{2}{3} I_{0}$
C

$I_{0} / 9$
D

$I_{0} / 6$

Solution

In 9 years, activity becomes $I = \frac{I_{0}}{3}$ .
In further 9 years, activity would become $I' = \frac{I \cdot}{3} = \frac{I_{0}}{3 \times 3} = \frac{I_{0}}{9}$ .

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