Q.
Activity of radioactive element decreased to one third of original activity R0 in 9 years. After further 9 years. its activity will be
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a
R0
b
23R0
c
R09
d
R06
answer is C.
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Detailed Solution
Activity R=R0e-λt R03=R0e-λ x 9⇒e-9λ=13 .......(i) After further 9 years R'=Re-λt=R03 x e-λ x 9 ......(ii) From equation (i) and (ii) R'=R09.
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