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Activity of radioactive element decreased to one third of original activity R0 in 9 years. After further 9 years. its activity will be

a
R0
b
23R0
c
R09
d
R06

detailed solution

Correct option is C

Activity R=R0e-λt R03=R0e-λ x 9⇒e-9λ=13     .......(i) After further 9 years R'=Re-λt=R03 x e-λ x 9  ......(ii) From equation (i) and (ii) R'=R09.

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