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Q.

The activity of a radioactive substance decreased to one third of original activity R0 in 9 years. After subsequent 9 years its activity will be

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a

R0

b

2R03

c

R09

d

R06

answer is C.

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Detailed Solution

t=0                       Rot=9yrs              13Rot=next⁡9yrs     R = R0218T=R032=R09⇒R03=R029T⇒13=129T
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