The activity of a radioactive substance is R at a time t and R/4 at time t = (t + T). Then mean life of the substance is

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T ln4

T ln2

Tln 4

Tln 2

answer is C.

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Detailed Solution

If R0 be the initial activity, R=R0 e-λt and R4=R0 e-λ(t+T)∴RR/4=e-λte-λ(t+T)⇒4=eλT⇒λ=ln 4T∴Mean life tm=1λ=Tln 4

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