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Questions  

The activity of a sample is 64 x 10-5 Ci. Its half—life is 3 days. The activity will become 5 x 10-6 Ci after

a
12 days
b
7 days
c
18 days
d
21 days

detailed solution

Correct option is D

A=A012t/T1/2⇒5 x 10-6=64 x 10-512t/3 ⇒1128=12t/3⇒t=21 days

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