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Temperature and heat-thermal properties of matter

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By Expert Faculty of Sri Chaitanya
Question

In an adiabatic process, the pressure of a monoatomic ideal gas increases by 0.5%. The volume will decrease by___%

Moderate
Solution

In an adiabatic process PVγ= constant (k).

Taking logarithm,

                     logP+γlogV=logk

                    Differentiating,

          ΔPP+γΔVV=0 ΔVV=1γΔPP

For a monoatomic gas, γ=53. Therefore ΔVV=35×0.5%=0.3%

The negative sign shows that the volume decreases.


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