Q.

In an adiabatic process, the pressure of a monoatomic ideal gas increases by 0.5%. The volume will decrease by___%

Moderate

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By Expert Faculty of Sri Chaitanya

answer is 0.3.

(Detailed Solution Below)

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Detailed Solution

In an adiabatic process PVγ= constant (k).Taking logarithm, log⁡P+γlog⁡V=log⁡k Differentiating, ΔPP+γΔVV=0⇒ ΔVV=−1γΔPPFor a monoatomic gas, γ=53. Therefore ΔVV=−35×0.5%=−0.3%The negative sign shows that the volume decreases.

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