In an adiabatic process, the pressure of a monoatomic ideal gas increases by 0.5%. The volume will decrease by___%

In an adiabatic process PVγ= constant (k).Taking logarithm,                     log⁡P+γlog⁡V=log⁡k                    Differentiating,          ΔPP+γΔVV=0⇒ ΔVV=−1γΔPPFor a monoatomic gas, γ=53. Therefore ΔVV=−35×0.5%=−0.3%The negative sign shows that the volume decreases.