In an adiabatic process wherein pressure is increased by 23% if CpCv = 32, then the volume decreases by about:
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a
49%
b
23%
c
4%
d
94%
answer is A.
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Detailed Solution
For an adiabatic process, PVγ = KHere, γ = 32 and K = constant PV32 = Klog P + 32log V = o log K∴ ∆PP+32∆VV = 0∴ ∆VV = -23∆PP∆VV×100 = -(23)(∆PP×100)% = -23×23% = -49%∴ Volume decreases by about 49%.