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Q.

The adjacent graph shows the extension (Δl) of a wire of length 1 m suspended from the top of a roof at one end and with a load w connected to the other end. If the cross-sectional area of the wire is 10-6 m2, calculate from the graph the Young's modulus of the material of the wire.

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a

1.0×1011 N/m2

b

2.0×1011 N/m2

c

4.0×1011 N/m2

d

6.0×1011 N/m2

answer is B.

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Detailed Solution

Δl=lYA·w⇒Δl∝wi.e. Δl versus w graph is a straight line passing through origin (as shown in question also), the slope of which is lYA.Slope =lYAY=lA1 slope =1.010-6(80-20)(4-1)×10-4=2.0×1011 N/m2

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The adjacent graph shows the extension (Δl) of a wire of length 1 m suspended from the top of a roof at one end and with a load w connected to the other end. If the cross-sectional area of the wire is 10-6 m2, calculate from the graph the Young's modulus of the material of the wire.