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Q.

In the adjoining circuit, the battery E1 has an e.m.f. of 12 volts and zero internal resistance while the battery E2 has an emf of 2 volts. If the galvanometer G reads zero, then the value of the resistance X (in ohms) is:

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a

10

b

100

c

14

d

200

answer is B.

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Detailed Solution

As there is no current through galvanometer.Hence VAB=2V 12=500i+2 ⇒i=150amp X⋅150=2 ⇒ X=100Ω

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In the adjoining circuit, the battery E1 has an e.m.f. of 12 volts and zero internal resistance while the battery E2 has an emf of 2 volts. If the galvanometer G reads zero, then the value of the resistance X (in ohms) is: