In the adjoining circuit, the emf of the cell is 2 volt and the internal resistance is negligible. The resistance of the voltmeter is 80 ohm. The reading of the voltmeter will be

detailed solution

Correct option is C

Total resistance of the circuit =802+ 20 =60 Ω⇒   Main  current,  i=260 = 130  ACombination of voltmeter and 80 Ω resistance is connected in series with 20 Ω so current through 20 Ω and this combination will be same, i.e., 130 A. Since the resistance of voltmeter is also 80 Ω, so this current is equally distributed in 80 Ω resistance and voltmeter i.e.,  160 A through each Potential difference across 80 Ω resistance  =160  ×  80=1.33  V