First slide

Parallel L-C-R circuit

Question

In the adjoining figure, the impedance of the circuit will be

Moderate

A

120 ohm
B

50 ohm
C

60 ohm
D

90 ohm

Solution

$i_{L} = \frac{90}{30} = 3 A, i_{C} = \frac{90}{20} = 4 .5 A$
Net current through circuit, $i = i_{C} - i_{L} = 1 .5 A$
$∴ Z = \frac{V}{i} = \frac{90}{1 .5} = 60 Ω$

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