First slide

Projection Under uniform Acceleration

Question

An aeroplane flying horizontally at an altitude of 490 m with a speed of 180 kmph drops a bomb. The horizontal distance at which it hits the ground is

Moderate

Solution

$u = 180 \times \frac{5}{{18}} = 50m{s^{ - 1}}$
$R = u\sqrt {\frac{{2h}}{g}} = 50\sqrt {\frac{{2 \times 490}}{{9.8}}} = 500m$

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