An aeroplane moving horizontally with a speed of 720 kmh-1 drops a food pocket, while flying at a height of 396.9 m. The time taken by a food pocket to reach the ground and its horizontal range is (Take 9 = 9.8 ms-2)
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a
3 s and 2000 m
b
5 s and 500 m
c
8 s and 1500 m
d
9 s and 1800 m
answer is D.
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Detailed Solution
T=2hg=2×396.99.8=9 sand u = 720km/h = 200 m/s∴ R = u x T = 200 x 9 = 1800 m