Question

An aeroplane moving horizontally with a speed of 720 kmh^-1 drops a food pocket, while flying at a height of 396.9 m. The time taken by a food pocket to reach the ground and its horizontal range is
(Take 9 = 9.8 ms^-2)

Moderate

Solution

$T = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 396.9}{9.8}} = 9 s$
and $u$ = 720km/h = 200 m/s
$∴$ R = $u$ x T = 200 x 9 = 1800 m

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