First slide

Magnetic flux and induced emf

Question

An aeroplane, with its wings spread 10m, is flying at a speed of 180km/h in a horizontal direction. The total intensity of earth’s field at that part is $2.5 \times 10^{- 4} W b / m^{2}$ and the angle of dip is $60^{o}$ . The emf induced between the tips of the plane wings will be ______

Moderate

A

108.25 mV
B

54.125 mV
C

88.37 mV
D

62.50mV

Solution

$\begin{array}{l} Vertical component of magnetic field, \\ B_{v} = B_{e} \sin δ = 2.5 \times 10^{- 4} \times \frac{\sqrt{3}}{2} T \\ E m f induced = B_{v} L v = 2.5 \times 10^{- 4} \times \frac{\sqrt{3}}{2} \times 10 \times 50 = 108.25 mV \end{array}$

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