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Q.

AIfa particles (m= 6.7x10-27 kg and q = 2e) arc accelerated from rest through a potential difference of 6 . 7 kV. Then they enter a magnetic field B = 0 .2 T perpendicular to their direction of motion. The radius of the path described by them is

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a

8.375m

b

8.375 cm

c

∞

d

none of the above

answer is B.

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Detailed Solution

12mv2=qV or v=2qVm1/2r=mVqB=mqB2qVm=1B2Vmq=10⋅22×6⋅7×103×6⋅7×10−271/22×1⋅6×10−19=8⋅375cm
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